array_sum
(PHP 4 >= 4.0.4, PHP 5, PHP 7, PHP 8)
array_sum — 对数组中所有值求和
参数
array-
输入的数组。
返回值
所有值的和以整数或浮点数的结果返回，array 为空时则返回 0。
更新日志
| 版本 | 说明 |
|---|---|
| 8.3.0 |
当 array 值不能转换为 int 或 float 时，现在会发出 E_WARNING。之前会忽略
array 和 object，而其它的值会转换为 int。此外，现在也会转换定义了数字转换的对象（比如 GMP）而不是忽略它。
|
示例
示例 #1 array_sum() 例子
<?php
$a = array(2, 4, 6, 8);
echo "sum(a) = " . array_sum($a) . "\n";
$b = array("a" => 1.2, "b" => 2.3, "c" => 3.4);
echo "sum(b) = " . array_sum($b) . "\n";
?>以上示例会输出：
sum(a) = 20 sum(b) = 6.9
＋添加备注
用户贡献的备注 2 notes
rodrigo at adboosters dot com ¶
3 years ago
If you want to calculate the sum in multi-dimensional arrays:
<?php
function array_multisum(array $arr): float {
$sum = array_sum($arr);
foreach($arr as $child) {
$sum += is_array($child) ? array_multisum($child) : 0;
}
return $sum;
}
?>
Example:
<?php
$data =
[
'a' => 5,
'b' =>
[
'c' => 7,
'd' => 3
],
'e' => 4,
'f' =>
[
'g' => 6,
'h' =>
[
'i' => 1,
'j' => 2
]
]
];
echo array_multisum($data);
//output: 28
?>
harl at gmail dot com ¶
2 years ago
array_sum() doesn't "ignore strings if they are not convertible", it converts them to zero. array_product() does the same thing, where the difference between "ignoring" and "converting to zero" is much more obvious.