get_resource_type

(PHP 4 >= 4.0.2, PHP 5, PHP 7, PHP 8)

get_resource_type — 返回资源（resource）类型

描述

get_resource_type(resource $handle): string

此函数返回一个字符串，用于表示传递给它的 resource 的类型。如果参数不是合法的 resource，将产生错误。


<?php
$c = mysql_connect();
echo get_resource_type($c)."\n";
// 打印：mysql link

$fp = fopen("foo","w");
echo get_resource_type($fp)."\n";
// 打印：file

$doc = new_xmldoc("1.0");
echo get_resource_type($doc->doc)."\n";
// 打印：domxml document
?>

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User Contributed Notes 1 note

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CertaiN ¶

8 years ago


Try this to know behavior:

<?php
function resource_test($resource, $name) {
    echo 
        '[' . $name. ']',
        PHP_EOL,
        '(bool)$resource => ',
        $resource ? 'TRUE' : 'FALSE',
        PHP_EOL,
        'get_resource_type($resource) => ',
        get_resource_type($resource) ?: 'FALSE',
        PHP_EOL,
        'is_resoruce($resource) => ',
        is_resource($resource) ? 'TRUE' : 'FALSE',
        PHP_EOL,
        PHP_EOL
    ;
}

$resource = tmpfile();
resource_test($resource, 'Check Valid Resource');

fclose($resource);
resource_test($resource, 'Check Released Resource');

$resource = null;
resource_test($resource, 'Check NULL');
?>

It will be shown as...

[Check Valid Resource]
(bool)$resource => TRUE
get_resource_type($resource) => stream
is_resoruce($resource) => TRUE

[Check Released Resource]
(bool)$resource => TRUE
get_resource_type($resource) => Unknown
is_resoruce($resource) => FALSE

[Check NULL]
(bool)$resource => FALSE
get_resource_type($resource) => FALSE
Warning:  get_resource_type() expects parameter 1 to be resource, null given in ... on line 10
is_resoruce($resource) => FALSE

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备份地址：http://www.lvesu.com/blog/php/function.get-resource-type.php