ReflectionClass::implementsInterface
(PHP 5, PHP 7, PHP 8)
ReflectionClass::implementsInterface — 接口的实现
说明
public ReflectionClass::implementsInterface(string
$interface): bool检查它是否实现了一个接口（interface）。
参数
-
interface -
接口（interface）的名称。
返回值
成功时返回 true， 或者在失败时返回 false。
参见
- ReflectionClass::isInterface() - 检查类是否是一个接口（interface）
- ReflectionClass::isSubclassOf() - 检查是否为一个子类
- interface_exists() - 检查接口是否已被定义
- Object Interfaces
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User Contributed Notes 3 notes
jtunaley at gmail dot com ¶
4 years ago
Note that this method also returns true when the thing you're reflecting is the interface you're checking for:
<?php
interface MyInterface {}
$reflect = new ReflectionClass('MyInterface');
var_dump($reflect->implementsInterface('MyInterface')); // bool(true)
?>
keepchen2016 at gmail dot com ¶
5 years ago
interface Factory
{
public function sayHello();
}
class ParentClass implements Factory
{
public function sayHello()
{
echo "hello\n";
}
}
class ChildrenClass extends ParentClass
{
}
$reflect = new ReflectionClass('ParentClass');
var_dump($reflect->implementsInterface('Factory'));
$second_ref = new ReflectionClass('ChildrenClass');
var_dump($second_ref->isSubclassOf('ParentClass'));
$third_ref = new ReflectionClass('Factory');
var_dump($third_ref->isInterface());
//can not be called as static
var_dump(ReflectionClass::isInterface('Factory'));
die;
//#result
bool(true)
bool(true)
bool(true)
PHP Fatal error: Non-static method ReflectionClass::isInterface() cannot be called statically
dhairya dot coder at gmail dot com ¶
6 years ago
//checks that whether class Fruit implements interface apple or not
interface Apple {
function taste();
}
class Fruit implements Apple {
function taste() {
echo "Seet";
}
}
$obj=new ReflectionClass('Fruit');
var_dump($obj->implementsInterface('Apple')); //Here it will checks that whether class Fruit implements interface apple or not
备份地址：http://www.lvesu.com/blog/php/reflectionclass.implementsinterface.php